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HomeSportDodgers' Yoshinobu Yamamoto leaves start vs. Kansas City after 2 innings...

Dodgers’ Yoshinobu Yamamoto leaves start vs. Kansas City after 2 innings due to triceps tightness

AP Photo/Mark J. Terrill
Los Angeles Dodgers starting pitcher Yoshinobu Yamamoto throws to the plate during the first inning of a baseball game against the Kansas City Royals on Saturday, June 15, 2024 in Los Angeles.

LOS ANGELES (AP) — Dodgers pitcher Yoshinobu Yamamoto left his start Saturday night against Kansas City after two innings because of triceps tightness.

The Japanese right-hander was postponed against Texas on Thursday for extra rest. He threw two-hit ball in seven innings with the New York Yankees on June 7. Yamamoto threw 106 pitches in that game and had thrown more than 100 in four consecutive starts through Saturday evening.

Yamamoto threw just 14 strikes on 28 pitches against the Royals. He allowed one hit and one walk with one strikeout.

This is Yamamoto’s first year in the Majors after signing a record $325 million, 12-year contract with the Dodgers in December. He is 6-2 with a 2.92 ERA.

Michael Grove replaced Yamamoto in the third inning.



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